Re: XSL-List Digest V3 #1090
> Date: Wed, 12 Sep 2001 13:55:40 +0200 > From: Bas Alberts <bas.alberts@xxxxxxxxxxxx> > Subject: RE: Getting the latest date > Since your dates are suitable for lexicographical ordering, > how about the following (almost literally copied from > http://www.dpawson.co.uk/xsl/sect2/N6461.html#d194e703): <xsl:variable name="maximum"> <xsl:for-each select="//revision"> <xsl:sort select="@date" order="descending" /> <xsl:if test="position() = 1"> <xsl:value-of select="."/> </xsl:if> </xsl:for-each> </xsl:variable> This didn't work. Suppose I put the revision elements in arbitrary order: <revision date="2000-04-20">1.0B</revision> <revision date="2000-04-21">1.0C</revision> <revision date="2000-04-19">1.0A</revision> I want the value "2000-04-21" but the code outputs "1.0B". It seems that no sorting happens. Original message: > > In a DTD I collect meta information about a document's history, like this: > > <revision date="2000-04-19">1.0A</revision> > <revision date="2000-04-20">1.0B</revision> > <revision date="2000-04-21">1.0C</revision> > > I need a way to pick out the latest date from these. The latest revision is > usually put on top of the others, but this may not always be the case. I > have considered converting the string "2000-04-19" to the number "20000419" > and then using the ceiling() function to get the latest date, but I'm > looking for a less complicated way of doing this. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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