Re: [xsl] catching the last node still satisfying a conditio

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Subject: Re: catching the last node still satisfying a condition
From: "Dimitar Peikov" <mitko@xxxxxxx>
Date: Thu, 13 Sep 2001 15:25:23 +0300

You can't without for-each cycle. because [] operands return 1 recordset not 
an array. You must set exact match that is enshured that only one element 
could contain this.

You possibly search for :

foos/foo[position() = last()]/bar[position() &lt; limit]




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Dimitar Peikov
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Current Thread
catching the last node still satisfying a condition Guillaume Rousse - Thu, 13 Sep 2001 08:10:46 -0400 (EDT) Dimitar Peikov - Thu, 13 Sep 2001 08:36:45 -0400 (EDT) <= Guillaume Rousse - Thu, 13 Sep 2001 09:00:00 -0400 (EDT) Dimitar Peikov - Thu, 13 Sep 2001 09:22:50 -0400 (EDT) Guillaume Rousse - Thu, 13 Sep 2001 09:43:47 -0400 (EDT) Michael Kay - Thu, 13 Sep 2001 10:01:57 -0400 (EDT)

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