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Matt--
Do just what he said, only qualify the match by whatever your criterial actually are. So, Chris had (modified slightly for conciseness): <xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template><xsl:template match="@Action"> <xsl:attribute name="Action">M</xsl:attribute> </xsl:template> But you want to do it for the <A> elements that met a certain criteria, such as @Id='X', as opposed to the whole document? So change that second template to <xsl:template match="A[@Id='X']//@Action"> <xsl:attribute name="Action">M</xsl:attribute> </xsl:template> or just <xsl:template match="A[@Id='X']//@Action"> <xsl:copy>M</xsl:copy> </xsl:template> Any Action attribute nodes anywhere inside an A whose Id='X', will be changed to have value "M". To explicate further, '//' is short for /descendant-or-self::node()/, so you are saying you want to match on any Action attribute attached to any A with Id='X', or attached to any descendant of such an A. It will fail to match Action attributes that are not attached to, or descendants of, such an A. This is a good example of how compact and elegant XSLT can get when you understand both the power of template matching and applying, and how to construct XPath expressions that match (or select) just what you want. Cheers, Wendell ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ====================================================================== XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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