Re: [xsl] Difference between preceding::foo[1] and (precedin

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Subject: Re: Difference between preceding::foo[1] and (preceding::foo)[1]
From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
Date: Thu, 06 Sep 2001 17:13:41 +0200

Zwetselaar M. van (Marco) wrote:

Now, I understand the syntactic difference between preceding::foo[1] and (preceding::foo)[1]. In the first expression, the predicate is part of a location path, whereas in the second it is applied to an expression. The fact that these two expressions select different nodes is also clear to me. What I don't understand is how the predicate could apply to a CHILD axis. WHOSE child axis?

I dont't think an axis can belong to something, it's only direction. See section 2.4 of XPath spec to grasp how predicate filters a nodeset. Axis is have to be known to evaluate proximity position of every node being filtered. So, filtering with respect to child axis implies document ordered sorting and taking into account elements only (because of child axis' principal node type).

--
Oleg Tkachenko
Multiconn International

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Current Thread
Difference between preceding::foo[1] and (preceding::foo)[1] Zwetselaar M. van (Marco) - Thu, 6 Sep 2001 09:20:28 -0400 (EDT) Jeni Tennison - Thu, 6 Sep 2001 10:14:02 -0400 (EDT) Oleg Tkachenko - Thu, 6 Sep 2001 10:21:41 -0400 (EDT) <= Oleg Tkachenko - Thu, 6 Sep 2001 11:16:41 -0400 (EDT) Michael Kay - Thu, 6 Sep 2001 10:55:16 -0400 (EDT)

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