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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Grouping headers revisted
 Hi,
First of all, thanks to everyone who answered my last question (about
grouping headers), you where all very helpful and I've learned from your
responses. Unfortunately my problem has turned out to be a bit more complex
than I previously thought. I've tried to work out a solution myself, but
it's a bit too complicated for my (limited) knowledge of xsl.
I have two parameters in my xsl 'discipline' and 'subdiscipline' and I have
the following xml:
<country name="The Netherlands">
<institutions>
<institution>
<name>School of pretentious art</name>
<city>Amsterdam</city>
<disciplines>
<discipline name="music">
<subdiscipline name="rock"/>
<subdiscipline name="free jazz"/>
</discipline>
</disciplines>
</institution>
<institution>
<name>Dendermalsen School of things</name>
<city>Dendermalsen</city>
<disciplines>
<discipline name="theatre" shortname="theatre">
<subdiscipline name="mime"/>
</discipline>
<discipline name="music">
<subdiscipline name="rock"/>
<subdiscipline name="free jazz"/>
</discipline>
</disciplines>
</institution>
<institution>
<name>School of music</name>
<city>Amsterdam</city>
<disciplines>
<discipline name="music">
<subdiscipline name="rock"/>
<subdiscipline name="free jazz"/>
</discipline>
</disciplines>
</institution>
<institution>
<name>School van artistieke dingen</name>
<city>Amsterdam</city>
<disciplines>
<discipline name="music">
<subdiscipline name="rock"/>
</discipline>
<discipline name="theatre">
<subdiscipline name="mime"/>
<subdiscipline name="drama"/>
</discipline>
</disciplines>
</institution>
</institutions>
</country>
I want to generate a list based on the parameters, so if I have param
'discipline' = music and param 'subsdiscipline' = free jazz I want to show
only the institutions that offer not only music, but only free jazz music,
so in this particular case 3 institutions will be shown. These parameters
are optional by the way, so one could also select just 'music'.
The thing that makes it more complicated is that I also want to group the
resulting institutions by city, so the previous example would result in:
Amsterdam
School of pretentious art
School of music
Dendermalsen
Dendermalsen School of things
Sorry for the long post, but this problem is making my head hurt :-)
This is the xsl I have so far, it's probably not very useful as it doesn't
really do what it's supposed to do but I'll include it anyway:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="discipline">music</xsl:param>
<xsl:param name="subdiscipline">free jazz</xsl:param>
<xsl:key name="disciplines" match="institution"
use="disciplines/discipline/@name"/>
<xsl:key name="subdisciplines" match="institution"
use="disciplines/discipline/subdiscipline/@name"/>
<xsl:key name="institutions" match="institution" use="city"/>
<xsl:template match="/">
<html>
<head>
<title></title>
</head>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="information">
</xsl:template>
<xsl:template match="institutions">
<xsl:apply-templates select="key('disciplines' , $discipline)">
<xsl:sort select="city" order="ascending"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="institution">
<br/>
<xsl:if test="generate-id() =
generate-id(key('institutions',city)[1])">
<b><xsl:value-of select="city"/></b><br/>
</xsl:if>
<xsl:apply-templates select="name"/>
<xsl:apply-templates select="disciplines"/>
</xsl:template>
<xsl:template match="institution/name">
<font color="red"><xsl:apply-templates/></font><br/>
</xsl:template>
<xsl:template match="disciplines">
<i>(<xsl:apply-templates/>)</i><br/>
</xsl:template>
<xsl:template match="discipline">
<xsl:value-of select="@name"/>,
</xsl:template>
</xsl:stylesheet>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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