|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: traversing the tree from an arbitrary node
There is no from-ancestors function i know of.
Whats wrong with:
<xsl:if test="@att='checkThis'">
<xsl:choose>
<xsl:when test="count(ancestor::
*)=count(following::childTag[1]/ancestor::*)">
<!-- do nothing since this is the right depth -->
</xsl:when>
<xsl:otherwise>
. . . error message . . .
</xsl:otherwise>
</xsl:choose>
</xsl:if>
Thanks, Joerg! That is exactly what I needed, but in a much simpler
statement!
Chris
+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
Chris d'Aquin, XML Engineer
Questia Media, Inc.
713.358.2515
cdaquin@xxxxxxxxxxx
http://www.questia.com/
+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|

Cart








