Re: detecting attribute node type
Oleg Tkachenko wrote: > Is there an efficient way to detect by XPath expression (not by a pattern) that > current node is an attribute node ? > I know solution like count(../@* | .)=count(../*), but I believe it's too > unefficient for this simple task. Hi Oleg, Most probably you ment not: > count(../@* | .)=count(../*) but: count(../@* | .)=count(../@*) There's another expression that evaluates to true only for an attribute node. The following will perform ***considerably faster*** with MSXML3 because of their very efficient implementation of the generate-id() function: generate-id() = generate-id(../@*[name()=name(current())]) Cheers, Dimitre Novatchev. --- Oleg Tkachenko Multiconn International __________________________________________________ Do You Yahoo!? Get personalized email addresses from Yahoo! Mail http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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