RE: building a nodeset from selected nodes

Hi Wendell,

Using key() is sooooo much easier than recursive templates.

At Thursday, July 05, 2001 8:52 AM, you wrote:
> (Even if it didn't, you could still iterate over the column children and 
> use . for that second argument. ;-)

I originally thought of doing this (assuming I understand you) but 
then I got back to the problem where I have multiple node-sets with 
no obvious (to me?) way to combine them into a single node-set, though 
I was eventually able to combine them using recursive template calls.  
Is there a simpler approach to combine a variable number of node-sets
into a single node-set (without using extensions)?

Thanks again,
-kurt

-----Original Message-----
From: Wendell Piez [mailto:wapiez@xxxxxxxxxxxxxxxx]
Sent: Thursday, July 05, 2001 8:52 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  building a nodeset from selected nodes


Hi Kurt,

At 05:26 PM 7/5/01, you wrote:
>Thanks, but doesn't the instruction:
>         <xsl:for-each select="key('columns-by-name', column)">
>get a node-set of columns where name=column?  I need an instruction
>that can get a node-set of columns where name IN (col1, col2, ...).

I see you've picked up the nice feature that that second argument can 
return a node-set and not be treated as a string.

(Even if it didn't, you could still iterate over the column children and 
use . for that second argument. ;-)

But as I said, we use keys so much for grouping, we forget the general case 
of what they're really for, "a way to work with documents that contain an 
implicit cross-reference structure" [XSLT 12].

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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