Re: sorting before transforming

Dan Miner wrote:

[snip]

> What I'd like to do is sort a list of nodes and then transform
> this sorted node list.  <xsl:sort> appears to only work on the
> resulting output and can not be applied to the input document.
> 
> Is it possible to sort nodes in the input?  If not, is there a way
> to "chain" stylesheets?  [ XML1 -> XSL1 -> XML2 -> XSL2 -> XML3, etc]

Hi Dan,

It is always possible to capture the result of sorting within a xsl:variable and
(after converting this RTF to a regular node-set using the xxx:node-set() extension
function) then to apply templates on the contents of this xsl:variable.

E.g.:

<xsl:variable name="vSorted">
  <xsl:for-each select="$employees">
    <xsl:sort select="@name"/>

    <xsl:copy-of select="."/>
  </xsl:for-each>
</xsl:variable>

<xsl:apply-templates select="msxsl:node-set($vSorted)/*"/>


Also have a look at the recent thread about multiple passes and the generic template
for multiple pass processing:

http://sources.redhat.com/ml/xsl-list/2001-06/msg01147.html

http://sources.redhat.com/ml/xsl-list/2001-07/msg00391.html


Hope this helped.

Cheers,
Dimitre Novatchev.


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