RE: getting XSL to ignore a line

> You must have in your XSL something like this :
> <xsl:output method="xml" ...
> doctype-system="blahblahblah"/>
> 
> Just remove the attribute doctype-system, so it
> become :
> <xsl:output method="xml" ... />

my xsl stylesheet does not have <xsl:output
method="xml" ... doctype-system="blahblahblah"/>

do i need it?  my looks like this:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"                
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:rdf="http://www.w3.org/1999/..."
    xmlns:moreover="http://w.moreover.com/">

<xsl:template match="/*">
    <rdf:RDF>
      <xsl:apply-templates select="article" />
    </rdf:RDF>
</xsl:template>

and so on...

i tried adding: <xsl:output method="xml"/> but it
still does not work.  

sorry I'm new to XML/XSL so I 'm not too familiar with
all this.

Samina

__________________________________________________
Do You Yahoo!?
Get personalized email addresses from Yahoo! Mail
http://personal.mail.yahoo.com/

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list