RE: captured in a <xsl:for-each>

Perhaps you want <xsl:for-each select="ancestor::title"/>? But even then,
you must avoid the code that processes the title element recursing to
process its descendant <kapitel> elements. Just modify the
<xsl:apply-templates> to be more selective.

Mike Kay
Software AG

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Roman
> Huditsch
> Sent: 23 July 2001 13:09
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  captured in a <xsl:for-each>
>
>
> Hi there!
>
> I seem to be captured in a for-each loop. Can someone please
> help me to
> escape and get the expected result?
>
> <xsl:template match="node()|@*">
> 	<xsl:copy>
>       		<xsl:apply-templates select="node()|@*"/>
>    	</xsl:copy>
> </xsl:template>
>
> <xsl:template match="kapitel">
> 	<xsl:for-each select="//title">           <!-- "title" is
> hierarchically above "kapital" -->
> 			<p>
> 				<xsl:apply-templates/>
> 			 </p>
> 		</xsl:for-each>
> </xsl:template>
>
> ...
>
>
>
> I would like to create a <p> tag for each title and within this
> paragraph I want to copy all the nodes and attributes as they
> are in the
> source file.
> But with the syntax above I just get an infinite template recursion.
> Could you please help me?
>
> Cheers,
> Roman
>
>
> > Roman Huditsch (RH )
> >
> _____________________________________________________________________
> > hico Informations- und Kommunikations-Management Gesellschaft m.b.H.
> > TechLab, Thomas A. Edison Straße 2.
> > A-7000 Eisenstadt / Austria
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> >
> >
>
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