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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Getting date of the XSL transformation into HTML o
 Ahhh I see your problem...I cant see anyway of passing a parameter using
those tools however I'm a newbie so what do I know? ;)
I should probably leave this reply to Rene but what the hell. Taking Rene's
example create an html file containing the following
<html>
<body>
<script type="text/javascript">
// Load your XSL
var objXSLT = new ActiveXObject("MSXML2.FreeThreadedDomDocument")
objXSLT.async = false
objXSLT.load("YourStylesheet.xsl")
// create a compiled XSL-object
var objCompiled = new ActiveXObject("MSXML2.XSLTemplate")
objCompiled.stylesheet = objXSLT.documentElement
// create XSL-processor
var objXSLProc = objCompiled.createProcessor()
// Load your XML
var objXML = new ActiveXObject("MSXML2.FreeThreadedDomDocument")
objXML.async = false
objXML.load("YourXML.xml")
// input for XSL-processor
objXSLProc.input = objXML
objXSLProc.addParameter("date", Date())
// etc.
// transform
objXSLProc.transform()
// display
document.write(objXSLProc.output)
</script>
</body>
</html>
Substitute the stylesheet and XML filenames as appropriate. Modify your
stylesheet and add in
<xsl:param name="date"/>
you can then access the date parameter you have passed by using
<xsl:value-of select="$date"/>
To view this of course you then have to load up the html file that you
created rather than executing the transformation through xmlspy.
Hope that helps rather than hinders (i.e. I hope I'm right and not leading
you up the garden path heheh )
Lee
-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Ghostrider
Sent: 20 July 2001 11:54
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: Getting date of the XSL transformation into HTML
output
Hi Rene (and Lee)
[it seems my previous reply didn't make the list for some reason so I'm
posting this again]
Rene wrote:
>I don't quite understand your problem.
>The date your XSL is generating the HTML is the current date isn't it?
Yes
>So why not use one of the suggestions how to get the current date and use
the
><xsl:value-of select="the current-date-function of your choice"/> to
hardcode
it into your HTML?
And what would that current-date-function look like? I really have no idea
(as
to syntax, use,...)!
>And if you're using msxml3 (or just IE) and want to know how to pass a
>parameter: see my earlier mail: http://www.biglist.com/lists/xsl-
>list/archives/200107/msg00002.html
I'm using XMLSpy and MSXML3.
I had a look at your example code but i don't know
1. where to put in my XSL
2. how to adapt it to so I get the current date in the output HTML
As to your reply, Lee:
Same problem: how do I use a param to actually get that date?
I'd appreciate any help on this (though i didn't think it would be this
complicated to get it done).
Thanks everyone,
Armin
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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