RE: How can I do the xsl file

And as usual several solutions for one problem:

	<xsl:template match="ITEM">
		<xsl:if test="AT/@ID='22'">
			<xsl:copy>
				<xsl:copy-of select="AT[@ID='22']"/>
			</xsl:copy>
		</xsl:if>
	</xsl:template>

Greetings Rene
   { @   @ }
        ^
      \__/

"You don't need eyes to see, you need vision!"

-----Oorspronkelijk bericht-----
Van:	laurence_zhang [SMTP:laurence_zhang@xxxxxxxx]
Verzonden:	donderdag 12 juli 2001 10:05
Aan:	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Onderwerp:	 How can I do the xsl file 

Hi,

I want to do convert from :
<ITEM ID="12"  CAPTION="first">
		<AT ID="11" SET="5"/>
		<AT ID="22" SET="5"/>
		<VALUE>1</VALUE>
</ITEM>
<ITEM ID="13"  CAPTION="sec">
		<AT ID="22" SET="5"/>
</ITEM>
<ITEM ID="14"  CAPTION="thr">
		<VALUE>0</VALUE>
</ITEM>


to:


<ITEM ID="12"  CAPTION="first">
		<AT ID="22" SET="5"/>
		<VALUE>1</VALUE>
</ITEM>
<ITEM ID="13"  CAPTION="sec">
		<AT ID="22" SET="5"/>
</ITEM>

that means:
1.remove element ATTR which ID=11;
2.remove item that have no ATTR ID=22.

How can I do the xsl file ?
Thanks a lot.

______________________________________

===================================================================
?AAEAa.N?c?OOEIa (http://mail.sina.com.cn)
??OAEO>u?I?AI.Io?AIA??IiIi???a?iE?E?EO>u?? (http://dailynews.sina.com.cn/c/272235.html)
??OAEO>u?I?A?????AIAA?Ii?A?A?iEO>u?o???? (http://dailynews.sina.com.cn/c/266499.html)

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list