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Re: Proper syntax for counting all prior nodes in XPat
Subject: Re: Proper syntax for counting all prior nodes in XPath?
From: Johannes Döbler <jd@xxxxxxxxxxxxxx>
Date: Mon, 11 Jun 2001 19:49:08 +0200
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Try the XPath expression 'count(preceding::* | ancestor::*)' to count all
the element nodes prior to the context node.
Johannes
At 11:16 11.06.01 -0600, you wrote:
Hi,
With an XML document like this:
<DOC>
<CHAPTER>
<SECTION>
<PAGE>
<LINE>Test</LINE>
<LINE>Test 2</LINE>
</PAGE>
</SECTION>
<SECTION>
<PAGE>
<LINE>Test 3</LINE>
</PAGE>
</SECTION>
</CHAPTER>
</DOC>
How can my XSL count all the preceding nodes? For example, when my template
is processing the <LINE>Test 3</LINE>, I want to count all nodes before it,
which would be 2 <LINE>s, 2 <PAGE>s, 2 <SECTION>s, 1 <CHAPTER>, and 1 <DOC>.
Does this make sense?
It would be something like <xsl:number level="any"
count="DOC|CHAPTER|SECTION|PAGE|LINE"/>, except I want to use the count in
an <xsl:if />, not just display it. I have tried using <xsl:if
test="count(something)">, but I do not know what the proper "something" is.
Any suggestions?
Thanks
Jason
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