RE: Count all the following nodes of a perticular pare

> how can i count following nodes of a perticular node, with a
> perticular parent.


If the context node is the second <branch>, then count(following-sibling::*)
(which I think is what I suggested when you first raised the question) will
return 2. Note that this is actually counting elements, not nodes.

Mike Kay
Software AG

> the xml is something like that:
> <root>
> 	<branch>
> 		<subBranch>
> 			.
> 			.
> 	<branch>
> 		<subBranch>
> 			.
> 			.
> 	<branch_anotherType>
>
> 		<subBranch>
> 			.
> 	<branch_anotherType>
>
> 		<subBranch>
> 			.
> 			.
> </root>	.
>
> actually i want to count how many child nodes exists after
> 2nd <branch>
> element.
> i expected to have 2 as the result
>
> thank you.
>
>
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>


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