Re: Putting parameter into XPATH expression
You are making it too hard. This does what you said you want: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method='text'/> <xsl:template match="/a"> <xsl:apply-templates select='b/c'/> </xsl:template> </xsl:stylesheet> Let the processor do the work, keep things simple. This code picks out the b/c nodes one after another and then the built-in default template outputs their text content. (Of course, you could make this into html instead of text if you want.) Cheers, Tom P [MacEwan, James (Information Services)] > In the code extract below, I always get the result "OneOneOne" instead of > "OneTwoThree" which I am expecting. > > I found a work around (based on my previous experience writing compilers) > that gets XSL processor to do what I want: "<xsl:value-of > select="a/b[$Position + 0 ]/c"/>" > > Can someone tell me a better (more correct) way to do this? > > XML ------------------ > <?xml version="1.0" encoding="ISO-8859-1"?> > <a> > <b> <c>One</c> </b> > <b> <c>Two</c> </b> > <b> <c>Three</c> </b> > </a> > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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