RE: Why is my xsl:param empty? (passed with xsl_with-p

Thanks Mike!

I've changed <xsl:template match="/"> into <xsl:template match="root"> and that did the trick!
But how could I know that "Built-in templates don't pass their parameters on to the templates they call."?
Why is that and is it in your book (XSLT 2nd) somewhere?

Greetings Rene
   { @   @ }
        ^
      \__/

"You don't need eyes to see, you need vision!"

-----Oorspronkelijk bericht-----
Van:	Michael Kay [SMTP:mhkay@xxxxxxxxxxxx]
Verzonden:	vrijdag 15 juni 2001 11:45
Aan:	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Onderwerp:	RE:  Why is my xsl:param empty? (passed with xsl_with-param)

> I'm playing around with xsl:with-param and xsl:param, but I
> cant get my param passed. What do I do wrong?

Your first template rule doesn't call the second one directly, it does so
via the built-in template for the <root> element. Built-in templates don't
pass their parameters on to the templates they call.

Mike Kay

> I expect:
>
> $trythis: 8
> $trythis: 8
>
> but I get
>
> $trythis:
> $trythis:
>
> xml:
> <root>
> 	<x>bla</x>
> 	<x>blabla</x>
> </root>
>
> xsl:
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> 	<xsl:template match="/">
>
> 		<xsl:apply-templates>
> 			<xsl:with-param name="trythis" select="8"/>
> 		</xsl:apply-templates>
>
> 	</xsl:template>
>
> 	<xsl:template match="x">
>
> 		<xsl:param name="trythis"/>
>
> 		<p>
> 			$trythis: <xsl:value-of select="$trythis"/>
> 		</p>
>
> 	</xsl:template>
>
> </xsl:stylesheet>
>
> Greetings Rene
>    { @   @ }
>         ^
>       \__/
>
> "You don't need eyes to see, you need vision!"
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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