RE: Problem in making choices using <xsl:choose>

Weird. Can you show us a complete stylesheet that demonstrates the problem,
and tell us which processor you're using?

Mike Kay
Software AG

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Sreekanth
> Pallavoor
> Sent: 01 June 2001 03:37
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Problem in making choices using <xsl:choose>
>
>
> Hi,
>
> I am new to XSLT. I am writing one XSLT program, where I need to print
> different output depending upon different conditions. But the
> code which
> checks for different conditions, doesn't seem to be working properly.
> The relevant part of code is given below. Here I have got a variable
> "state" getting set to some state code which comes from some external
> source. If it's value is AZ, I want to print "Arizona" and if
> it's value
> is anything else then I want to print "Other". The result I am getting
> is, it always prints "Arizona" even if $state is set to
> something other
> than "AZ". (To double-check, I am printing the $state value
> also in the
> output. Even if it is CA, the output I still get is "CA
> Arizona" and not
> "CA Other").
>
> Can someone tell me what could be the reason.
>
> Thanks.
> -- Sreekanth
>
> <xsl:template match="headline">
>   <xsl:choose>
>     <xsl:when test="contains($state,'AZ')">
>       <font face="{$headline-font}"
> size="{$headline-size}"><xsl:value-of select="$state"/>
> Arizona </font>
>     </xsl:when>
>     <xsl:otherwise>
>       <font face="{$headline-font}"
> size="{$headline-size}"><xsl:value-of select="$state"/> Other </font>
>     </xsl:otherwise>
>   </xsl:choose>
> </xsl:template>
>
>
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>


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