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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: XSL to generate XPaths
> Here I needed to check if the current node is an element: > > count(.|../*)=count(../*) and count(../*[name()=name(current())]) > 1" Perhaps self::* in the first place is more efficient? (self::* selects element nodes only) Cheers, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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