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RE: grouping adjacent siblings

Subject: RE: grouping adjacent siblings
From: utah@xxxxxxxxxxxxxxx
Date: Thu, 3 May 2001 13:02:18 -0400 (EDT)
RE:  grouping adjacent siblings
On Thu, 3 May 2001, Michael Kay wrote:

> > I am trying to transform the following...
> >
> > <frag>
> >  <b>house</b>
> >  <a>door</a>
> >  <a>wall</a>
> >  <a>room</a>
> >  <b>barn</b>
> >  <a>hay</a>
> >  <a>cow</a>
> >  <a>poo</a>
> > </frag>
> >
> You can do this with something like
>  <xsl:for-each select="b">
>     <xsl:variable name="id" select="generate-id()"/>
>    <xsl:apply-templates/>
>    <xsl:for-each
>  select="following-sibling::a[generate-id(preceding-sibling::b[1])=$id]">
>     <xsl:apply-templates/>
>    </xsl:for-each>
>   </xsl:for-each>
> Mike Kay
> Software AG

thanks Michael...
just to make sure i understand before i proceed...
so I generate a unique id for the current context of <<b>>...
(which defines a local variable named $id) then I select following <<a>>
siblings using the condition that the preceding <<b>> sibling must have
the same id. Therefore if the following <<a>> occurs after the following
<<b>> it is not included in the result...
thanks again..

Utah Ingersoll

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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