|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] jumping out of a loop revisited
I am a bit confused. The problem is that I don't know the position of the
References and LinksForGenus children (may vary) for which different
processing will apply:
Grasslands is the parent.
I have 3 potential templates:
1. Is there a way I can say select all children except where child name is
LinksForTheGenus and References in the top for-each statement:
<xsl:for-each select="Grasslands/*[position()>3 and text()]">
<h3><font color="#00007f"><i><xsl:value-of
select="name()"/></i></font></h3>
<p><font color="#008000"><xsl:value-of select="."/></font></p>
</xsl:for-each>
2. <xsl:template match= "Grasslands/LinksForTheGenus/Link">
<h3><a NAME="Label0045"></a><font color="#00007F"><i>Links for the
genus:</i></font></h3>
<ul>
<xsl:for-each select="Grasslands/LinksForTheGenus/Link">
<li><font color="#008000"> <xsl:value-of
select="Address"/>;
<xsl:value-of select="Name"/> </font></li>
</xsl:for-each>
</ul>
</xsl:template>
3. <xsl:template match="Grasslands/References/Ref">
<font color="#008000"> <xsl:value-of select="Name"/>
 <xsl:value-of
select="Year"/>;
</font>
</xsl:for-each>
</xsl:template>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|

Cart








