RE: xsl to xsl doing it right

Hello List,

Thanks for all your help.  There's something weird going on though in my
attempt to implement your suggestions.
Here is my namespace aliasing code...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:alex=
"alex-namespace" >
<xsl:namespace-alias stylesheet-prefix="xsl" result-prefix="alex"/>
<xsl:output method="xsl"/>
<xsl:template match="/">
<alex:stylesheet version="1.0">

The xml is processed correctly and everything seems to work properly
except....In the output alex is not replaced with xsl.

hmmmmm.....
Any more suggestions?
Thanks again!
Alex



-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Simon Wickes
Sent: Tuesday, April 03, 2001 4:26 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  xsl to xsl doing it right


At 03:57 PM 4/3/01 -0400, you wrote:
>Hello,
>I'm trying to output an xsl using xsl and am having a hard time
>distinguishing which parts i want the processor to actually process and
>which parts are meant to be straight output.  <xsl:text> doesn't seem to be
>any help and <![CDATA escapes all the brackets making the output useless.
>Any suggestions?

Doh.

OK, the preferred method is to use namespace-alias:

<xsl:namespace-alias stylesheet-prefix="simon" result-prefix="xsl"/>

and then your xsl looks like this

<xsl:template match="/">
<simon:template match="whatever">....

much cleaner.


Simon

xmlgeek@xxxxxxxxx


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