Re: Transform min and max values to list?

<xsl:call-template name="for.loop">
        <xsl:with-param name="i">1</xsl:with-param>
        <xsl:with-param name="count">10</xsl:with-param>
</xsl:call-template>

<xsl:template name="for.loop">
        <xsl:param name="i"/>
        <xsl:param name="count"/>
        <xsl:if test="$i &lt;= $count">
<!--    body of the loop goes here    -->
        </xsl:if>
        <xsl:if test="$i &lt;= $count">
                <xsl:call-template name="for.loop">

                        <xsl:with-param name="i">
                                <!-- Increment index-->
                                <xsl:value-of select="$i + 1"/>
                        </xsl:with-param>
                        <xsl:with-param name="count">
                                <xsl:value-of select="$count"/>
                        </xsl:with-param>
                </xsl:call-template>
        </xsl:if>
</xsl:template>
(code-bit in XML cooktop!)

I want to transform this element:

<number min="1" max="3"/>

into this:

<select>
  <option>1</option>
  <option>2</option>
  <option>3</option>
</select>

I have looked at for-each but its select attribute requires a node-set. Is
there a simple way to achieve what I want?

Thanks in advance.

--
Michael Strasser
Brisbane, Australia

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