Subject: Re: Displaying grid of elements in table with the position() call for input names?
From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx>
Date: Thu, 8 Mar 2001 09:10:06 +0000
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Hi Kevin,
> This works fine. But now, I have dilema..I need to display a random
> number of fields horizontally as well. Each row has the same number
> of fields across horizontally. So, the name should be something like
> SomeName_rowNum_colNum. However, since the position() call seems to
> be giving me the row number, what happens when I use it in this
> context..where by I am in the row loop and now building the column
> of fields. Does position() give me the number of fields in the
> current xsl:for-each loop? If so, how can I access the "outer"
> xsl:for-each loops count?
You just need to store it in a variable:
<xsl:for-each select="$rows">
<xsl:variable name="rowNum" select="position()" />
<xsl:for-each select="$cols">
<xsl:variable name="colNum" select="position()" />
<input type="text" name="SomeName_{$rowNum}_{$colNum}" />
</xsl:for-each>
</xsl:for-each>
I hope that helps,
Jeni
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Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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