RE: sorting question
> I'm trying to transform a list of elements into a sorted set > of pairs, and > haven't > been able to determine how to get the 'next' sorted element > relative to the current position. This definitely calls for a two-pass approach, one to sort the data and the second to group it. > > I checked out the xsl faq, and I found a posting of > Jeni's that showed how to copy a sorted list into a variable, but > it doesn't seem to be working for me. > (I'm using MSXML3 in case that matters...) > > <xsl:variable name="letterlist"> > <xsl:for-each select="/ALPHABET/LETTER"> > <xsl:sort select="." /> > <xsl:copy-of select="." /> > </xsl:for-each> > </xsl:variable> > > <!-- nothing comes out... --> > <xsl:value-of select="$letterlist" /> > It should, I think, be the concatenation of the letters. Mike Kay Software AG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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