Subject: Re: Copy XHTML element contents without base tag
From: cutlass <cutlass@xxxxxxxxxxx>
Date: Fri, 09 Mar 2001 13:09:38 +0000
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look at faq on copying
http://www.dpawson.co.uk/xsl/N1930.html
Nick Vincent wrote:
Hi all,
This is probably painfully easy, but I can't think of a solution:
I need to include a raw XHTML fragment in my XSL:
<document>
<xfragment>
This is a fragment of XHTML
<table><tr><td>
[snip dull HTML]
</td></tr></table>
</xfragment>
</document>
Now, as far as I can see there are two ways of processing this in XSLT:
<xsl:template match="xfragment">
<xsl:copy-of select="." />
</xsl:template>
Unfortunately this ends up including the <xfragment> tags in the output,
which I can't really have.
The other way I can see is
<xsl:template match="xfragment">
<xsl:copy-of select="./*" />
</xsl:template>
Unfortunately this removes any text elements which are direct children of
the xfragment tags (e.g. the phrase 'This is a fragment of XHTML' in the
above example).
Does anyone know any better ways of making this copy?
Thanks,
Nick Vincent
NeoWorks
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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