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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Function position()
I have the following xml-structure:
Chapter
/ \
/ \
Paragraph Paragraph
/ | \ \ / | \
/ | \ \ etc.
/ | \ \
/ | \ \
Text StretchText Text StretchText
Now I need in each StretchText-Node the number of itself.
That means what is the number of the StretchText - node if I look at
the whole tree. So I can count ALL Stretchtext-nodes from 1 to n.
If I use 'position()' I only get the node number of Stretchtext from the node 'Paragraph',
So each Stretchtext child is countet from 1 to m in each Paragraph,
but I need to count in the whole tree.
I used the following:
<xsl:template match"Chapter">
<xsl:apply-template select="Paragraph"/>
</xsl:template>
<xsl:template match"Paragraph">
<xsl:value-of select="Text"/>
<xsl:apply-template select="StretchText"/>
</xsl:template>
<xsl:template match"StretchText">
<xsl:value-of select="position()"/> ---> THIS doesn't work in my case.
</xsl:template>
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Isn't it possible to do like the following: can't I tell the function 'position()' to count
the StretchText-nodes from the root node and not from Paragraph????
Things like <xsl:value-of select="Chapter//StretchText[position()]"/> does not work.
Thank you.
Partho
_______________________________________________________________________
Partho Paul email: uk4u@xxxxxxxxxxxxxxxxxxx
Computer science student or: paul@xxxxxxxxx
-----------------------------------------------------------------------
Homepage: http://www.partho.de
Durga Puja: http://www.uni-karlsruhe.de/~uk4u/durga.html
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