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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Position() of parent node
Can anyone provide me with the syntax for getting the position() value of
the current nodes' parent node (and the parent parent etc. position()
value). I seem only able to return the current position().
I need to use the value in my generated HTML, not for template selection.
Thanks for any help.
Simon Cansick
sc@xxxxxxxxxxxxxxxxxxx
Access Accounting Ltd
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The Old School, Stratford St Mary,
Colchester, Essex. CO7 6LZ, United Kingdom.
Phone +44 (0) 1206 322575
Fax +44 (0) 1206 322956
Internet http://www.access-accounts.com
http://www.accessweb.co.uk
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Access Accounts - The Brand Leader in e-commerce financials
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