Re: Finding the maximun number of nodes

Actually even simpler:

	count(//tr[not(key('numCells', count(td) + 1))]/td)

--- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:

> Use:
> 
> <xsl:key name="numCells" match="tr" use="count(td)"/>
> 
> <xsl:template name="maxCols">
>   <xsl:for-each select="//tr[not(key('numCells', count(td) + 1))]">
> 	
> 	    <xsl:value-of select="count(td)"/>
>   </xsl:for-each>		
> </xsl:template>


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