showing unique element values only

Good day everyone,
I haven't posted a question in a while, but this one's got me..
consider the following xmlDoc structure..
====================
<FeeDetailsResponse>
	<ACHFee feeID="xx">
		<feeType>BuyRate</feeType>
		<feeLevelBottom>.00</feeLevelBottom>
		<feeLevelTop>1,000</feeLevelTop>
		<feeVolumeBottom>1</feeVolumeBottom>
		<feeVolumeTop>1,000</feeVolumeTop>
		<feeSubmissionBottom>1</feeSubmissionBottom>
		<feeSubmissionTop>1,000</feeSubmissionTop>
		<feeAmount>xx</feeAmount>
		<feePercent>xx</feePercent>
	</ACHFee>
	<ACHFee feeID="xx">
	...
	</ACHFee>
	etc. etc.
</FeeDetailsResponse>
===================
What I have been trying to accomplish  is creating a table-formatted page
that goes through each ACHFee/feeLevelBottom, feeVolumeBottom and
feeSubmissionBottom and builds a cell. In the cell I have the current()
Bottom element using format-number(), then it's
following-sibling::fee------Top, also using format-number().  The same type
of table is set up for each of the 'bottom' elements.  Since this is a
'fee-structure' table, infinite combinations can be created.  Using
functions such as 'split' or 'combine'(ie, split the first 0-1,000 cell into
a 0-500 cell and a 500.01-1,000 cell or combine a 0-1,000 cell with a
1,001-infinity cell)
I've tried manipulating the order of the ACHFee element with  <xsl:sort
select="feeLevelBottom"/> and so-on. I've used every combination of
preceding::,  following::, following-sibling:: that I can come up with, but
I still cannot make ONLY UNIQUE cell contents be displayed
========================snippet of xsl ==========
<xsl:for-each select="//ACHFee/feeLevelBottom">
<xsl:sort select="."/>
<xsl:if test="position()='1' or position()=last() or number(.) !=
number(preceding::*/feeLevelBottom)"><!--also used
preceding::ACHFee/feeLevelBottom and about a million other variations-->
	<form name="xxx" id="Level" class="AdjustBuyRate">
	<input type="hidden" name="feeLevelBottom"..>
		<xsl:attribute name="value"><xsl:value-of select="."/></xsl:attribute>
	</input>
	<input type="hidden" name="feeLevelTop" ...>
		<xsl:attribute name="value"><xsl:value-of
select="following-sibling::feeLevelTop"/></xsl:attribute>
	</input>
	<td align="center" valign="middle">
		===============this is just for my testing=======
	<br/>this=<xsl:value-of select="number(.)"/><br/><!-- this gives the
correct number-->
	preceding=<xsl:value-of
select="number(preceding::ACHFee/feeLevelBottom)"/><br/><!--this however
gives me the previous number in reverse document order, not  sort order,
there for my preceding !=  current test fails and the cell contents get
displayed-->
		=================================================
	<xsl:value-of select="format-number(.,'$#,###,###.00')"/><xsl:text> -
</xsl:text><xsl:if test="following-sibling::feeLevelTop
&gt;'0'"><xsl:value-of
select="format-number(following-sibling::feeLevelTop,'$##.00')"/></xsl:if><b
r/>
	<input type="text" name="splitLevel" ...>
		<xsl:attribute name="class">L<xsl:value-of
select="../@feeID"/></xsl:attribute>
	</input>
	<xsl:text>   </xsl:text>
	<input type="button"
name="splitL"...onclick="javascript:AdjustFees(this.form,'splitL','{@feeID}'
)"/>
	<br/>
	<xsl:if test="position()!='1'">
	<input type="button" name="combineL"...onclick="javascript:AdjustFees
(this.form,'combineL','{@feeID}')"/>
	</xsl:if>
	</td>
	</form>
	</xsl:if>
	</xsl:for-each>

any ideas on how to get this accomplished would be greatly appreciated!
thanks,
kb
Keith Brooks
Software Developer
Global eTelecom
Keith@xxxxxxxxxxxxxxxxxx


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