RE: xml to xml transform

Thanks, Mike, for the clue. However, when I tested
this solution, I paid attention that if the source
xml is slightly different:
<rows>
  <row fld="f1" value="v1"/>
  <row fld="f1" value="v2"/>
  <row fld="f2" value="v3"/>
  <row fld="f1" value="v2"/>
  <row fld="f3" value="v4"/>
</rows>

then this solution will not work since f1 comes after f2
and in this case I'll see two elements f1 rather than one.
Should I sort the entire collection before I use this
solution? Can I use sorting capabilities of apply-templates
for that?

Thanks again!

Shimon

> -----Original Message-----
> From: Mike Brown [mailto:mike@xxxxxxxx]
> Sent: Monday, January 15, 2001 10:54 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Cc: spozin@xxxxxxxxxxxxx
> Subject: Re:  xml to xml transform
> 
> 
> Shimon Pozin wrote:
> > How can I transform document:
> > <row @fld="f1" value="v1">
> > <row @fld="f1" value="v2">
> > <row @fld="f2" value="v3">
> > <row @fld="f3" value="v4">
> 
> This isn't even XML.
> I will answer your question based on the assumption that you meant:
> 
> <rows>
> <row fld="f1" value="v1"/>
> <row fld="f1" value="v2"/>
> <row fld="f2" value="v3"/>
> <row fld="f3" value="v4"/>
> </rows>
> 
> > to
> > 
> > <f1>
> > <v1/>
> > <v2/>
> > </f1>
> > <f2>
> > <v3/>
> > </f2>
> > <f3>
> > <v4/>
> > </f3>
> > 
> > if I don't know values f1, f2, etc. in advance?
> 
> This is a fun (fun in a pathetically geeky way) variation on 
> the grouping
> FAQ. There is a design pattern for this. In your case it is along the
> lines of the following:
> 
>   1. id a node-set representing the unique values from all the @fld
>        attributes (one f1, one f2, one f3...). create an element with
>        a name that is the same as the value. in the content of that
>        element...
>   2. iterate through that set, finding the rest of the @fld 
> values that
>        have the current value (all f1s, all f2s, all f3s...). 
> There's your
>        group. All you have to do is...
>   3. Iterate through those (or in this case, through the corresponding
>        @value attributes) and create elements named for their values.
> 
> <?xml version="1.0" encoding="utf-8"?>
> <xsl:stylesheet 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
> 
>         <xsl:output method="xml" indent="yes"/>
> 
>         <xsl:template match="rows">
>            <xsl:for-each select="row[not(@fld = 
> preceding-sibling::row/@fld)]"> 
>               <xsl:element name="{@fld}">
>                  <xsl:for-each select="../row[@fld = current()/@fld]">
>                     <xsl:element name="{@value}"/>
>                  </xsl:for-each>
>               </xsl:element>
>            </xsl:for-each>
>         </xsl:template>
> 
> </xsl:stylesheet>
> 
>    - Mike
> ____________________________________________________________________
> Mike J. Brown, software engineer at            My XML/XSL resources: 
> webb.net in Denver, Colorado, USA              http://skew.org/xml/
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list