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How to select distinct combined element values

Subject: How to select distinct combined element values
From: "Albert Tsun" <albert.tsun@xxxxxxxxxxxx>
Date: Thu, 21 Dec 2000 12:06:15 +0800
select distinct group

Dear All,

I got a problem in getting distinct element group values.

XML source:
+++++++++++
<match>
     <date>1-11-2000</date>
     <team>Brazil</team>
     <group>A</group>
     <score>1</score>
</match>
<match>
     <date>2-11-2000</date>
     <team>Brazil</team>
     <group>A</group>
     <score>1</score>
</match>
<match>
     <date>1-11-2000</date>
     <team>Brazil</team>
     <group>B</group>
     <score>1</score>
</match>
<match>
     <date>1-11-2000</date>
     <team>Argentina</team>
     <group>A</group>
     <score>1</score>
</match>
<match>
     <date>1-11-2000</date>
     <team>Argentina</team>
     <group>A</group>
     <score>1</score>
</match>

 for distinct team :
In XSL, I can use
     <xsl:variable name="teams" select = "//team[not(.=preceding::team)]"/>
to get
     Brazil
     Argentina

However, if I want to get distinct team, group, that is
     Brazil A
     Brazil B
     Argentina A

How can I do it ? would Mike give me some suggestion ?

TIA




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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