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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: select following-siblings, but not all of them
Francis, your example code helped me flesh out the suggestions yesterday of Ken Meltsner in his reply to my "creating XML hierarchy where not existed before??" post. thank you one, thank you all. //F --- Francis Norton <francis@xxxxxxxxxxx> wrote: > > use the following transform: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="text" version="1.0" > indent="yes"/> > <xsl:template match="/"> > <xsl:for-each select="/dataset/name"> > <xsl:variable name="key" select="."/> > <xsl:value-of select="concat(., ' ')"/> > <!-- get all following remark elements for > which this is the > nearest preceding name --> > <xsl:for-each > select="following-sibling::remark[count(preceding-sibling::name[1] > | > $key) = 1]"> > <xsl:value-of select="concat(., ' ')"/> > </xsl:for-each> > </xsl:for-each> > </xsl:template> > </xsl:stylesheet> > __________________________________________________ Do You Yahoo!? Yahoo! Shopping - Thousands of Stores. Millions of Products. http://shopping.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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