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RE: getting parents position

Subject: RE: getting parents position
From: "Kevin Jones" <kjouk@xxxxxxxxxxx>
Date: Wed, 8 Nov 2000 11:07:03 -0000
javascript getting parent

> 
> <xsl:template name="tableCell">
> <xsl:choose>
> <!-- ???
>  every other row should be shaded... this isnt right. Basicly I need the
> syntax for getting the value of a parents position()  
> ???-->
> 	<xsl:when test="parent[position() mod 2 = 0]">
> 			<td class="tableshadedRow"><xsl:value-of
> select="parent" /><xsl:value-of select="$cellData" /></td>
> 	</xsl:when>
> 	<xsl:otherwise>
> 			<td><xsl:value-of select="$cellData" /></td>	
> 	</xsl:otherwise>	
> </xsl:choose>
> 

I don't think you can get this easily once your in the second template. 
An simple solution would be to pass the position from the calling 
template as you are doing with $celldata.

Kev.

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