RE: question with using Muenchian/xsl:key (Re: sort/group/co

My original code was trying exactly what you have suggested, but unfortunely
it creates invalid XSL due to xsl:key is top-level element, so it can not be
an element inside templates.

Xiaocun

-----Original Message-----
From: Goetz Bock
To: xsl-list@xxxxxxxxxxxxxxxx
Sent: 11/11/00 3:33 PM
Subject: Re: question with using Muenchian/xsl:key (Re: sort/group/count
probl em)


On Sat, Nov 11 '00 at 13:47, Xu, Xiaocun wrote:
> [ ...] 
> key('items-by-itemid', @itemid) returns all items with the same
@itemid in
> the entire XML document.  I just want all items with the same @itemid
in
> each of the itemlist element, how can I do that?
What about creating the key inside the template that matches itemlist?

<xsl:template match="itemlist">
  <xsl:key ...>

</xsl:template>

Not tried, but shoud work,
    Goetz.


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