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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Transforming XML to XML
Hello everybody ! I'm a newbie to XML/XSL so maybe my question may look trivial: How do I transform a XML document into another XML document? My problem actually is to write a XSL transformation rule that creates the XML docuement description: <?xml version="1.0" encoding="UTF-8"?> I've tried to following XSL syle sheet: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format"> <xsl:template match="/"> <xsl:processing-instruction name="xml">version="1.0" encoding="UTF-8"</xsl:processing-instruction> </xsl:template> </xsl:stylesheet> Unfortunately I couldn't find any example which shows how to transform XML to XML !! :( At the moment I'm even not sure if the specification allows such transformations. I hope someone can help me here. Zeljko XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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