Re: rendering Xlink from a XML by using XSL

Handren Ahmed wrote:
> 
> hi!
> 
> That was exactly what I meant!

:) 

> I did write following code but it doesn't work either.
> In my xml file I wrote:
> 
> <Adress xlink:type="simple" xlink:href="http://www.dsv.su.se"
> xlink:show="new"
> xmlns:xlink="http://www.w3.org/TR/xlink/"
> >Klick here</Adress>
> 
> In my xsl file I try to show that link by writing the follwing code:
> <xsl:template match="*[@xlink:href]">
>         <xsl:value-of select="."/>
> </xsl:template>
> 
> How can I use Xlink? How can I click on the xlink:-)? 

In this case, you'll probably want to generate some (X)HTML to visualize
this link.

To generate a (X)HTML hypertext link, you just need to generate a
classical "a" element:

<xsl:template match="*[@xlink:href]">
  <a href="{@xlink:href}">
    <xsl:apply-templates/>
  </a>
</xsl:template>

And, if you want to handle the xlink:show="new", you can add a more
restrictive template that will be higher priority when xlink:show has
this value:

<xsl:template match="*[@xlink:href and @xlink:show='new']">
  <a href="{@xlink:href}" target="_blank">
    <xsl:apply-templates/>
  </a>
</xsl:template>

Hope this helps.

Eric
-- 
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Eric van der Vlist       Dyomedea                    http://dyomedea.com
http://xmlfr.org         http://4xt.org              http://ducotede.com
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