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RE: How to delete empty element tag from output XML?

Subject: RE: How to delete empty element tag from output XML?
From: "Guangzu Wang (Houston)" <Guangzu.Wang@xxxxxxxxxxxxxx>
Date: Wed, 25 Oct 2000 12:35:25 -0400
Thank you Michael for your help. I try your suggestion but still have
trouble. Maybe my question is not clear before. I give a scenario below.

Input XML:
<?xml version="1.0" encoding="UTF-8"?>
		<N3 />
		<Sex />

Expected output XML:
<?xml version="1.0" encoding="UTF-8"?>

You may notice 
1). if <Sex> is empty as in Amy case, don't print <Gender /> 
2). if <N3> is empty as in Tom case, I need a output <MI>N/A</MI>, i.e. a
default of "N/A".
3). the structure and tag of output different with input.
As I mentioned before, the last thing I want to do is use <xsl:if> in XSLT
stylesheet to compare every segment because it's too tedious given the fact
I have numberous tags need to process.

Thanks again. have a good day.


-----Original Message-----
From: Kay Michael [mailto:Michael.Kay@xxxxxxx]
Sent: Wednesday, October 25, 2000 4:32 AM
To: 'xsl-list@xxxxxxxxxxxxxxxx'
Subject: RE: How to delete empty element tag from output XML?

> I use XSLT to convert XML to XML and HTML. I need to delete 
> the tag when
> there are no value in the output. for example, I have XSLT as 
> following:
> 	<NAME><xsl:value-of select="N1" /></NAME>
> I don't need <NAME /> or <NAME> </NAME>.
> One way I can do it is use <xsl:if> outside of <Name> tag, 
> but that's too
> much for me because I have a lot of similar tags.

<xsl:template match="*" mode="copy-unless-empty">
 <xsl:if test="node()">
   <xsl:copy-of select="@*"/>
   <xsl:value-of select="."/>

and then use <xsl:apply-templates mode="copy-unless-empty"/>
to process these elements.

> Another related question is that some time I need put a 
> default value if nothing there.

A similar technique should do the trick.

Mike Kay 

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