RE: Testing position of parent

>    if the parent is an <LG> which has first position among its
>    siblings, then do X, otherwise do Y

Try test="parent::lg[not(preceding-sibling::*)]"
> 
> Here's what I thought would be the expression to accomplish that:
> 
>    <xsl:when test="parent::lg[position()=1]">

This looks at its position among all the parent::lg elements of the current
node

Mike Kay 


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