RE: XSLT and Default namespaces

Raimond,

first of all, what parser are you using ??? I guess it's the MS one as in
the second question you refer to their implementation.

Now, if you using the MS parser in the July version there is a problem with
the namespace implementation. I haven't tested the new version (September)
to that respect yet ... but MS said that they fixing it ...

Try this as a workaround in the meanwhile

	<xsl:copy-of select="*[local-name='a']/*[local-name='b']"/>

I think name() should work as well in this case (default namespace).

I post you a message I sent to the list some time ago that contains a
description of the problem and some test code (anyone else interested send
me a mail).

Axel

> -----Original Message-----
> From: Raimond Brookman [mailto:nucleon@xxxxxxxxxx]
> Sent: Thursday, October 05, 2000 9:03 PM
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: XSLT and Default namespaces
> 
> 
> Hi,
> 
> I want to transform an xml document that has declared a namespace, for
> example:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <test xmlns="myns">
>  <a>
>   <b></b>
>  </a>
> </test>
> 
> The corresponding XSLT is:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>  <xsl:output method="xml" version="1.0" encoding="UTF-8" 
> indent="yes"/>
> 
>  <xsl:template match="/">
>   <xsl:copy-of select="a/b"/>
>  </xsl:template>
> </xsl:stylesheet>
> 
> The resulting output document is empty.
> When i dont use a default namespace and prefix the root 
> elements in the
> source document, and also declare the namespace in the XSL 
> and use it in my
> X-path, it works:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <x:test xmlns:x="myns">
>  <a>
>   <b></b>
>  </a>
> </x:test>
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>  xmlns:x="myns">
>  <xsl:output method="xml" version="1.0" encoding="UTF-8" 
> indent="yes"/>
> 
>  <xsl:template match="/">
>   <xsl:copy-of select="x:test/a/b"/>
>  </xsl:template>
> </xsl:stylesheet>
> 
> Result:
> <?xml version="1.0" encoding="UTF-16"?>
> <b xmlns:x="myns"></b>
> 
> So, after this lengthy introduction the following questions:
> 1. Is there a way to make this work without having to 
> contantly prefix all
> my xpath queries
> 2. Secondly, MS has come up with XDR, which is declared as follows:
>     xmlns="x-schema:myschema.xdr"
>     The problem is, that automatic validating happens in this 
> case in tools
> such as XML spy. I cant find a way to declare that namespace 
> inside an XSLT
> without having problems running the XLST because validation 
> kicks in.....
> 
> Anybody know some workarounds for these things?
> 
> Grtz,
> Raimond
> 
> 
> 
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> 


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