XSL attribute expression

I am fairly new to XSL and am trying to extract the value of the attribute
'url' from the node 'job' and make it a HTML <A HREF=> link. Is this the
correct syntax? Instead of getting 
<A HREF="http://www.apago.com/jobs/1">URL</A>
I am getting
<A HREF="{@url}">URL</A>

here is my xml file fragment:

<job job-id="100" url="http://www.apago.com/jobs/1" />

and my xsl fragment:

<xsl:template match="job">
	<DIV>
	Job <xsl:value-of select="@job-id" />
	<A HREF="{@url}">URL</A>
	</DIV>
</xsl:template>

Thanks,
-- 
Dwight Kelly
Apago, a division of Essential Technical Services, Inc.  
315 Allen Street Cumming, GA 30040
voice:(770) 889-2848  fax:(770) 889-2624 Internet:dkelly@xxxxxxxxx
http://www.apago.com


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