Subject: RE: How to declare a param which name is in a XML file?
From: Kay Michael <Michael.Kay@xxxxxxx>
Date: Thu, 26 Oct 2000 13:44:46 +0100
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> <xsl:param name="@ident"/>
>
> But when XSLT-parser(SAXON) processes it, shows this error:
>
> "Name @ident contains invalid characters"
>
> How should i solve this problem??
>
Do it a different way.
Saxon extends the things you can do at run-time considerably, compared to
the XSLT standard, but declaring variables whose name is decided at run-time
is definitely out of bounds!
A lot of people seem to thing of variables as textual substitution macros.
They aren't. It can only be a matter of time before someone tries:
<xsl:$declare name="x" select="y"/>
with $declare set to "variable" or "param"
Mike Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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