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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Standard problem?
> This is, to every node I'd like to have
> all its parents and their siblings, I'd also like to
> have the node and it's siblings and the direct
> childs of the node.
Isn't that just "I'd like to have all direct children of any ancestor.
I think you want something like
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
>
<xsl:strip-space elements="*"/>
<xsl:output method="xml" indent="yes"/>
<xsl:param name="thisid" select="'A1'"/>
<xsl:template match="*">
<xsl:if test="../descendant-or-self::*[@id=$thisid]">
<xsl:copy>
<xsl:copy-of select="@id"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
<?xml version="1.0" encoding="utf-8"?>
<x>
<NODE id="A">
<NODE id="A1"/>
<NODE id="A2"/>
<NODE id="A3">
<NODE id="A3i"/>
<NODE id="A3ii"/>
</NODE>
</NODE>
<NODE id="B"/>
<NODE id="C"/>
</x>
David
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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