RE: XSLT: DTD referencing

A question from a newbie to XSLT:

I am using an editor XML Spy 3.0, while cross checking the XSLT template I
am given an error: Unable to locate a supported schema, reference kind.
Where exactly do I reference the DTD. Here's the code.

<?xml version="1.0" encoding="UTF-8"?>
 <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="html" version="1.0" encoding="UTF-8"
indent="yes" doctype-public="-//W3C//DTD HTML 4.0 Transitional//EN"/>
	<xsl:template match="/">

Cheers,
The Novice
 


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