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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Using xsl:if to determine if a node is empty.
I am fairly new to XML/XSL. In fact I am writing my first XSL for a
production environment. I am trying to determine if a node is empty so that
I can print a line or not. I have tried several different variations of
template matching and xsl:if statements and have not been able to get
anywhere.
Here is the latest thing that I have tried which seems to match evertime
through so the text is coming out even on empty tags.
<xsl:template match="VENDOR_ITEM_NUM">
<xsl:variable name="empty_tag"></xsl:variable>
<tr>
<td></td>
<td>
<font size="2">
<xsl:if test="$empty_tag != .">
<xsl:value-of select="concat('Vendor Item number:
',.)"/>
</xsl:if>
</font>
</td>
</tr>
</xsl:template>
Any help would be greatly appreciated.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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