Re: newbie variable question
if there are any grp/type element whose contents are "DMA" I want to print out the value of the associated name in that grp. if there is no grp/type element whose contents is "DMA" I want to print out the values of the description element. [XML:] <area> <grp> <type>MSA</type> <name>foo</type> </grp> <grp> <type>DMA</type> <name>bar</type> </grp> </area> <description>baz</description>
The error makes sense. XSLT variables are in effect ("in scope") only within the block of code in which they're defined. Your stylesheet is structured in part like this:
Begin for-each.... If some condition.... Define variable $ValueExists End if End for-each
If some condition.... Do something with $ValueExists End if
See? The if-block doesn't know anything about $ValueExists. The second, standalone if-block can't "see into" the if-block which contains the variable's definition; the variable goes out of scope when that if-block closes.
You can sometimes get around the problem by declaring the variable globally -- that is, make the <xsl:variable...> element a top-level element (child of <xsl:stylesheet>). I say sometimes because you can't always get at some information that would be readily available from within a template rule.
Might be better in your case to simply instantiate one template for type="DMA" and a different one for type!="DMA", using those expressions as predicates.
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