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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: sorting the unique elements
> Applying the described approach (the muenchian method) I get
> the following
> stylesheet:
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:key name="elements" match="*" use="name()" />
>
> <xsl:template match="/">
> <xsl:for-each select="//*[generate-id() =
> generate-id(key('elements',name())[1])]">
> <xsl:sort select="name()" />
> <xsl:value-of select="name()" />
> </xsl:for-each>
> </xsl:template>
>
> </xsl:stylesheet>
Thank you, after trying lots of example codes and lots of methods this (the
most elementary) one does the job I wanted. Again, thank you for this
solution.
David Valera
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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