Re: Image in XSL?

Joe,

Just a few quick tips:

As you aren't renaming any of the attributes,

<img>
  <xsl:attribute name="src">
  <xsl:value-of select="image-clear1/@src" /> 
  </xsl:attribute>
  <xsl:attribute name="width">
  <xsl:value-of select="image-clear1/@width" /> 
  </xsl:attribute>
  <xsl:attribute name="height">
  <xsl:value-of select="image-clear1/@height" /> 
  </xsl:attribute>
</img>

could more easily be written as:

<img>
  <xsl:copy-of select="image-clear1/@src |
                       image-clear1/@width |
                       image-clear1/@height" />
</img>

In other words, make copies of the 'src', 'width' and 'height' attributes
of 'image-clear1' to be placed in the new 'img' element.

If image-clear1 only defines src, width and height attributes (as it did in
your example), then you could do:

<img>
  <xsl:copy-of select="image-clear1/@*" />
</img>

In other words, make copies of all the attributes on image-clear1.

Since you're dealing with 'image-clear1', 'image-clear2' and 'image-logo'
in almost exactly the same way, it may be worth creating a template that
does the same thing for each:

<xsl:template match="image-clear1 | image-clear2 | image-logo">
      <!-- or match="*[starts-with(name(), 'image-')]" -->
  <img>
    <xsl:copy-of select="@*" />
  </img>
</xsl:template>

And then applying it to the separate nodes explicitly within your table:

<table>
  <xsl:for-each select="homepage/pagecontents/top">
    <tr>
      <td><xsl:apply-templates select="image-clear1" /></td>
      <td><xsl:apply-templates select="image-clear2" /></td>
      <td valign="top" align="left">
        <xsl:apply-templates select="image-logo" />
      </td>
    </tr>
  </xsl:for-each>
</table>

Sorry, I know you weren't looking for a critique, but I just couldn't help
myself :)

Cheers,

Jeni

Dr Jeni Tennison
Epistemics Ltd * Strelley Hall * Nottingham * NG8 6PE
tel: 0115 906 1301 * fax: 0115 906 1304 * email: jeni.tennison@xxxxxxxxxxxxxxxx


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