Standard XPath expression for the intersection of two node s
Michael Kay is the person, who discovered the XPath expression for the intersection of two node-sets. Therefore, there's no need for a node-set intersection extension function. You can find this in http://p2p.wrox.com --> markup --> xslt, message #46 of a set of 95. Must I say that I enjoyed reading his book enormously!!! Here's Mike's reply to my suggestion that intersecting two node-sets doesn't need an extension function: ----------------------------------- Date: Tue, 11 Jul 2000 09:25:14 +0100 Author: Kay Michael <Michael.Kay@xxxxxxx> Subject: Re: Q: An efficient way to test if a node belongs to a node list Body: > I believe this is not true! Here's how to output the > intersection of two node-sets, ... > > MHK: But saying things can't be done is dangerous, it wouldn't > surprise me to be proved wrong on this one. I had a think about this in the bath. The following expression finds the intersection of $ns1 and $ns2 $ns1[count(.|$ns2)=count($ns2)] So I've proved myself wrong before anyone else got the chance to do it first. Mike Kay -------------- Original message ---------------- Date: Wed, 2 Aug 2000 09:56:58 +0100 From: Kay Michael <Michael.Kay@xxxxxxx> Subject: RE: How can I test if an node included in a nodeset > I have a selected a nodeset in a variable($nodeset) and now I > would compare this nodeset to an node and I would detect if this node > included in the nodeset. > This is surprisingly difficult. Saxon and xt both provide intersection() as an extension function. The only way of doing it within the standard is to rely on union: count($nodeset) = count($nodeset | $node) will be true iff $node is a member of $nodeset. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list __________________________________________________ Do You Yahoo!? Kick off your party with Yahoo! Invites. http://invites.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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