AW: Passing an URL as a parameter with Xalan

Marco,
I'm not quite sure, but you might want to try forward slashes instead of
back slashes in the file name.

Hope this helps,
Christian


> -----Ursprüngliche Nachricht-----
> Von: Marco.Mistroni@xxxxxxxxx [mailto:Marco.Mistroni@xxxxxxxxx]
> Gesendet am: Montag, 31. Juli 2000 10:22
> An: xsl-list@xxxxxxxxxxxxxxxx
> Betreff: Passing an URL as a parameter with Xalan
> 
> hi all,
> 	i have a problem:
> i have defined in my stylesheet an xsl:param
> now i want at run-time to pass an URL to that parameter
> 
> i tried with file:///c:\mydir\layout.xml as value of hte parameter
> 
> however, the XSLProcessor continues to give me the error
> 
> XSL Error: pattern = 'c:\mydir\layout.xml'
> Extra illegal tokens: 'mydir', '\', 'layout.xml', style tree 
> node: org.ap
> ache.xalan.xslt.StylesheetRoot@2a5ce2b7
> XSL Error: SAX Exception
> There was a SAX Exception!
> org.apache.xalan.xslt.XSLProcessorException: pattern = 
> 'c:\mydir\layout.x
> ml'
> Extra illegal tokens: 'marcodev', '\', 'layouthtml.xml'
>         at
> org.apache.xalan.xslt.XSLTEngineImpl.error(XSLTEngineImpl.java:1630)
>         at
> org.apache.xalan.xslt.XSLTEngineImpl.error(XSLTEngineImpl.java:1594)
>         at 
> org.apache.xalan.xslt.XSLTEngineImpl.process(XSLTEngineImpl.java,
> Com
> 
> 
> i am using the latest version of Xalan
> 
> can anybody help me??
> thanx in advance & regards
> 	marco
> 
> 
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> 


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